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Welcome!!! This blog is being created by Grade 12 students at the SVRSS. Similar to all collaborations on the web, this blog will be as useful and as worthwhile as YOU make it...Post often, and enjoy learning with each other...
4 comments:
i'm not very good at this but for question 12 i did normalcdf(168,195,176,7) and i got 87.01%... i think this is the percentage that DOES qualify though.... i tried to do it a different way and i got like...umm .3% which doesn't seem right... unless its 3%... anyone know what i did wrong?
I also used the normailcdf function on my calculator to figure out the first part of this question...
I typed in..
normalcdf(10.5,11.5,12.7,2.1) and it shoult turn out to be about 13.6% probability that your tires will be between 10.5-11.5
For the second part i got the Z-score to be -.33
For 15a igot 13.64%. I got the same answer from both Shadenorm(10.5,11.5,12.7,2.1) and from Normalcdf(10.5,11.5,12.7,2.1).
For 15b I got a Z-score of -0.66667 by calculating the percentage from X-bar to -1X-bar that 12 mm was.
for 15c I haven't got anything.
I used the cdf method for a.) and got 14%
And for B.) I used the Z= method and got -.33. and i didnt get C.)
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